Roof truss Wind load calculation as per is 875-2015

In this article we explain wind load calculation on roof truss as per revised is code 875 -2015. Explained all steps of wind load calculation with solved example. So read the article till the end and comment if you got anything wrong in this article.

Steps of  roof truss Wind load calculation as per is 875-2015.

Step-1 : Angle of roof truss

Angle of roof truss = tan-1( Rise/(Span/2))

Step-2 : Determining Basic wind Speed (Vb)

Finding basic wind speed from page no 6 or 51 of  IS 875 part-3 -2015 as per location.

Step-3: Wind pressure calculation

1. Design Wind Speed (Vz) :

For finding design wind speed, formula given on page no 5 of IS 875 part-3 2015.

Vz = Vb × K1 ×K2 × K3 × K4

Where,

Vb = Basic wind speed

K1 = Risk Coefficient

K2 = Terrain roughness and height factor

K3 = Topography factor

K4 = Importance factor for cyclonic region

Find K1

K1 is obtain from page no 7, table-1, IS 875 part-3 2015

K1 is depends on class and life of structure.

Best Book for Design of steel structure see on Amazon

Find K2

 K2 is depends on terrain category and height of structure.

Terrain category decided on the basis of terrain of location of structure.

K2 is obtain from table-2, page no 8, IS 875 part-3 2015

Find K3

K3 is obtain from clause 6.3.3, page no 8, IS 875 part-3 2015.

Find K4

K4 is obtain fro clause no 6.3.4, page no 8, IS 875 part-3 2015.

For hospital, schools, communication towers, cyclone shelters, K4 is 1.30.

For industrial structures, K4 is 1.15.

All other structures, K4 is 1.00.

2. Design Wind Pressure:

Pd = Kd ×Ka × Kc × Pz

Where,

Pz = wind pressure

Pz = 0.6 × Vz2

Kd = wind directionality factor

Ka = Area averaging factor.

Kc = Combination factor.

Find Kd

Kd is obtain from clause no 7.2.1, page no 9, IS 875 part-3 2015.

Find Ka

Ka is obtain from clause no 7.2.2, page no 10, IS 875 part-3 2015.

Ka  is depends on tributary area.

Tributary area = spacing or pitch × rise

Limit state Design of steel structure book on Amazon

Find Kc

Kc is obtain from clause no 7.3.3.13, page no16, IS 875 part-3 2015.

Step-4: Wind load on individual members

Wind load on individual members is determined by formula which is given in IS 875 part 3, clause 7.3.1, page no 10.

F = ( Cpe – Cpi ) A × Pd

Where,

Cpe  = external pressure coefficient

Cpi = internal pressure coefficient

A = surface area of structural element or cladding unit

Pd = design wind pressure

Find Cpi

Cpi is obtain from clause 7.3.2, page no 11, IS 875 part 3 2015.

Cpi is depends on opening area in a structure.

Find Cpe

Cpe  is obtain from clause 7.3.3, page no 11, IS 875 part-3 2015.

Cpe is also obtain from table 6, IS 875 part-3 2015.

Solved example of Wind load calculation as per IS 875-2015

Roofing system of an industrial shed consists of trusses spaced at 6 m apart. The span of roof truss is18 m and rise is 3 m. The level of eaves is 7 m above the ground. Assume suitable configuration of truss.  The shade is situated on flat terrain with sparsely populated buildings. The shed has less than 20% permeability. Prepare structural layout of industrial steel shed with suitable configuration. Determine the wind forces on the truss. Location Chennai.

Given Data:

  • Spacing : 6m
  • Span = 18m
  • Rise = 3m
  • Height = 7m
  • Terrain: flat terrain with sparsely populated buildings
  • Shed has less than 20% permeability

Solution:

Assume howe type truss for 18m span.

howe type truss

Step-1: Angle of roof truss

Angle of roof truss = tan-1( Rise/(Span/2))

= tan-1(3/(18/2))

= 18.43

Get Design of steel structure by N . Subramanian Book on amazon

Step-2: Determining Basic wind Speed (Vb)

For Chennai, the basic wind speed is 50m/s from page no51, IS 875 part-3 2015.

Step-3: Wind pressure calculation

Direct finding K1, K2, K3,  K4 from the IS 875 part-3. For find this coefficient is explain above in steps.

  • K1 = 1
  • K2 = 1
  • K3 = 1
  • K4 = 1.15

Vz = Vb × K1 ×K2 × K3 × K4

= 50 × 1 × 1 × 1 × 1.15

= 57.5m/s

Design Wind Pressure:

Pd = Kd ×Ka × Kc × Pz

Direct finding Kd, Ka, Kc from the IS 875 part-3. For find this coefficient is explain above in steps.

  • K= 0.9
  • Ka = 0.92 (getting this by interpolation between 10 and 25)
  • Kc = 0.9

Pz = 0.6 × Vz2

= 0.6 × 57.52

=1983.75 N/m2

Pd = Kd ×Ka × Kc × Pz

= 0.9 × 0.92 × 0.9 × 1983.75

= 1478.29 N/m2

= 1.478 KN/m2

Design wind pressure is less than 0.7 × Pz

= 0.7 × 1983.75

= 1388.62 (N/m2)   Hence OK

Step-4: Wind load on individual members

F = ( Cpe – Cpi ) A × Pd

Find Cpi

The shed has less than 20% permeability

Therefore, Cpi = +/-(0.5)

Find Cpe

For truss angle 18.43 and,

h/w = 7/18

= 0.38

the Cpe is given below.

wind load coefficient calculation

Finding area:

A = Spacing × ( ((span/2)2 × (rise)2)^(0.5))/number of panels )

=  6 × (((9)2 × (3)2) ^ (0.5)) / 8 )

= 7.115 m2

Therefore,

A × Pd  = 7.115 × 1.478

= 10.52 KN

Wind load calculation table

wind load calculation details

Also read:

Leave a Comment